Web"`A B C D E` is a regular pentagon. The bisector of `/_A` of the pentagon meets the side `C D` in `Mdot` Show that `/_A M C=90^0dot`" WebTriangle ABE is isosceles, its base angles have sum 180 -108 = 72 Each base angle is half that, so angle ABE has measure 36 . Angle AED is an interior angle of the regular pentagon, so it has measure 108 . Angle AEB is the other base angle of the isosceles triangle ABE, so it is 36 . Angle BED = Angle AED - Angle AEB = 108 -36 = 72 Edwin
See answer: please help!! a regular pentagon ABCDE is shown
WebMar 30, 2024 · Question 29 (OR 1st question) In the figure, ABCDE is a pentagon with BE ∥ CD and BC ∥ DE. BC is perpendicular to CD. AB = 5cm, AE = 5cm, BE = 7cm, BC = x − y ... WebDec 4, 2024 · The sum of the interior angles = 540°. Let A, B , C = D - 50. And let E = D. So we have. A + B + C + D + E =540. (D -50) + (D -50) + (D -50) + D + D = 540. 5D - 150 = 540. 5D = 690. D = 690 / 5 = 138°. incirlik weather
SOLUTION: Line segment AC is a diagonal of regular …
WebJan 7, 2024 · Since ABCDE is a regular pentagon and OCD is an equilateral triangle AB = BC = CD = DE = EA = OC = OD We know, each interior angle of a regular pentagon is 108° WebLine segment AC is a diagonal of 'regular pentagon' ABCDE. What is the measure of angle ACD Yes! [(180)(n-2)/n], the measure of each interior angle is 108 degrees Note Editing: … Weba) What is the angle between AC and BE? b) What is the angle between AC and the tangent line to the circumcircle of this pentagon at D? Show transcribed image text incontinence pads knickers