In an ap the sum of first ten terms is - 150
WebHere, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a 10. For the … WebExpert Answer Transcribed image text: 3. The third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative [5] 4.
In an ap the sum of first ten terms is - 150
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WebHere, we are given S 10 = - 150 and sum of the next ten terms is - 550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a 10. First term = a. Last term = a 10. As, a n = a + ( n - 1) d. For the 10 th term, a 10 = a + ( 10 - 1) d. = a + 9 d. So, here we can find the sum of the n terms of the ... WebOct 10, 2024 · In an AP of 50 terms, the sum of first 10 terms is 210 and the sum of its last 15 terms is 2565. Find the A.P. The sum of the first five terms of an AP and the sum of …
WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty … WebFor an AP, the sum of the first n terms can be calculated if the first term, common difference and the total terms are known. The formula for the arithmetic progression sum is explained below: Consider an AP …
WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. WebThe sum of first 10 terms of an AP is -150 and the sum of its next 10 terms is -550. Find the AP. Solution Let a be the first term and d be the common difference of the AP. Then, It is …
WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = …
WebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. dancing with the stars punsWebApr 8, 2024 · Given sum of first ten terms = − 150. We know that Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d] Therefore, ⇒ S 10 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ … birling family treeWebFind the sum of the first 10 terms of the arithmetic sequence given by A1=28 and d=4. Answers: 3 Get Iba pang mga katanungan: Math. Math, 28.10.2024 21:29, kenn14. Jancent knows that ab = xy and ac = xz. what other information must he know to prove ∆abc ≅ ∆xyz by sas postulate? ... birling family relationshipsWebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same? dancing with the stars rankings last nightWebOct 20, 2024 · Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. ⇒ -150= 10/2 [ 2a + 9d ] ⇒ … birling family tree inspector callsWebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border birling family quotesWebLe a1, a2, ..., a10 are terms of an A.P given S10 = a1+a2+...+10 = 150 But we know that: s10 = (a1+a10)*10/2 = 150 ==> a1+a10 = 150/5 ==> a1+a10 = 30 ==> a10 = 30 - a1...... (1) But a10... birling gap cliff fall